Accenture hires freshers in India as Associate Software Engineer (ASE) or Advanced ASE through one online process: a cognitive and technical assessment, a coding round, a spoken-English communication assessment and a short technical/HR interview. Your coding score decides the track; candidates report ASE at ₹4.5 LPA and Advanced ASE at ₹6.5 LPA.
Who can apply
- BE/BTech, MCA or MSc (CS/IT) degree
- No active backlogs at application or onboarding
- Percentage cutoff is set per drive; PrepInsta reports 65% or 6.5 CGPA in graduation
Key facts
Popular problems to start with
Interview process
- 1Cognitive and technical assessmentOne reported pattern: 90 MCQs in 90 minutes on English, critical and abstract reasoning, MS Office, pseudocode and networking/security/cloud. Newer drives report a game-based cognitive test.
- 2Coding roundReported: 2 questions (easy + medium) in 45 minutes, mostly arrays and strings, any language. This score decides ASE vs Advanced ASE.
- 3Communication assessmentAI-graded spoken English: reading aloud, sentence repetition, short answers, story retelling and open speaking. Candidates report it as mandatory but non-eliminatory.
- 4Technical + HR interviewShort virtual interview (reported 7-15 minutes) on your projects, OOP/DBMS basics, certifications and why Accenture.
Questions to expect in Accenture interviews
Drawn from reported fresher tests and interviews (sources below), with short answers. Practise more on placd.
Find the maximum subarray sum of a given array.
Kadane's algorithm: set cur = best = a[0]; for each later element, cur = max(a[i], cur + a[i]) and best = max(best, cur). Starting from a[0] (not 0) makes an all-negative array return its largest element. One pass: O(n) time, O(1) space.
Return the sum of the two largest numbers in an array.
Track first and second largest in one pass: if x > first, set second = first and first = x; else if x > second, set second = x. Initialise both to the smallest possible value. Answer = first + second. O(n) time, O(1) space; sorting also works in O(n log n).
Given two strings, find the difference between their numbers of spaces and say whether that difference is odd or even.
Count the ' ' characters in each string with one loop each, take d = |c1 - c2|, print d and 'Even' if d % 2 == 0, else 'Odd'. O(n + m) time, O(1) space. Confirm from the sample output whether the absolute difference is expected.
Given an array of temperatures, find the length of the longest monotonically decreasing subarray.
Scan once with len = 1 and best = 1: if t[i] < t[i-1], len++, else reset len = 1; update best = max(best, len). O(n) time, O(1) space. If equal neighbours should count as non-increasing, use <= instead of <; check the sample.
Two Sum: given an array and a target, return the indices of two numbers that add up to the target.
Use a hash map from value to index. For each x at index i, if target - x is already in the map, return [map[target - x], i]; otherwise store x -> i. O(n) time, O(n) space. Brute force is O(n^2); sorting with two pointers is O(n log n).
Explain the difference between HTML, CSS and JavaScript.
HTML defines a page's structure and content (headings, links, forms). CSS controls presentation: layout, colours, fonts and responsiveness. JavaScript adds behaviour: it runs in the browser, handles events, validates input and updates the DOM or fetches data without reloading. HTML and CSS are markup/style languages; JavaScript is a programming language.
About Accenture hiring
What is the difference between ASE and Advanced ASE at Accenture?
Both come from the same application and tests; your coding round performance decides the track. Candidates and PrepInsta report ASE at ₹4.5 LPA and Advanced ASE at ₹6.5 LPA. FacePrep quotes wider bands (₹4.5–6.5 and ₹6.5–9 LPA), so treat your offer letter as final.
Is the Accenture communication assessment an elimination round?
Candidates on GeeksforGeeks describe it as mandatory but non-eliminatory: an AI-graded spoken-English test with reading aloud, sentence repetition, question answering and story retelling. The cognitive/technical assessment and the coding round are the elimination stages.
What percentage do I need for Accenture?
Accenture sets the cutoff per drive, so read your job posting or college notice. PrepInsta reports 65% or 6.5 CGPA in graduation for recent drives. No active backlogs at application and at onboarding is required in every drive.
Sources
- Accenture Interview Experience for ASE | On-campus - GeeksforGeeks
- Accenture Recruitment Process 2025 for Freshers - PrepInsta
- Accenture Recruitment 2026: Eligibility & Exam Pattern - FacePrep
- Accenture Interview Experience for ASE and AASE (On-Campus, Batch 2025) - GeeksforGeeks
- Accenture Interview Experience For Associate Software Engineer - GeeksforGeeks
- Accenture Interview Experience for ASE / Advanced ASE - GeeksforGeeks
Checked on 25 Sep 2026. Recruitment rules change each cycle — confirm dates and eligibility in the official notification.